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Let us suppose that a child is walking on the plane. His orbit is
given by the two functions of time
and
.
Suppose now that the child is pulling some toy, to which he is connected
by a rigid bar of length a. We are interested in computing the orbit of
the toy when the child is walking around. Let
be the
position of the toy. Based on these relationships we can formulate the
following equations:
- The distance between then point
and
is
always the length of the bar. Therefore

- The toy is moving always in the direction of the bar. Therefore the
difference vector of the two positions is some multiple of the velocity
vector of the toy
:

with
.
- The absolute value of the velocity of the toy depends on the
direction of the velocity vector of the child
. Assume e.g.
that the child is walking on a circle of radius a (length of the bar).
In this special case the toy will stay in the center of the circle and not
move at all.
In general, the absolute value of the velocity of the toy is given by the
absolute value of the projection of the velocity of the child onto the bar.
Dinesh Manocha
Sat Mar 14 11:51:29 EST 1998