Here is the source code that I used when I talked about the assignment. (Don't forget that it's not due until Wednesday, June 14th now!)

import PairOfDice;

public class testDice
{
    public static void main(String[] args)
    {
        int value;
 
        // declares a reference do a PairOfDice object
        PairOfDice myDice;
 
        // instantiates a PairOfDice object
        myDice = new PairOfDice();
 
        // calls the roll method to randomly choose face values
        //    for the two dice
        // similar to the physical act of rolling the two dice
        myDice.roll();
 
        // calls the getFaceValue method to find out the face of ONE
        //    of the two dice
        // similar to the physical act of looking at one of the two dice
        value = myDice.getFaceValue(myDice.DIE_1);
 
        // calls the getFaceValue method to find out the face of the
        //    other of the two dice
        // similar to the physical act of looking at the other of the
        //    two dice.
        value = myDice.getFaceValue(myDice.DIE_2);
    }
}

// primitive data and assignment
int a;
int b;
 
a = 7;
b = 30;
 
b = a;
 
if (b == a)
    System.out.println("a and b are equal");
 
// objects
Coin coin1;
Coin coin2;

// the following line is an error because coin1 doesn't
//   point to (refer to) a valid object. It currently
//   has the value of the null reference
coin1.flip();
 
coin1 = new Coin();
coin2 = new Coin();
 
// this prints out "coin1 and coin2 are different objects"
if (coin1 == coin2)
    System.out.println("coin1 and coin2 are the same object");
else
    System.out.println("coin1 and coin2 are different objects");
 
coin1 = coin2;

// this prints out "coin1 and coin2 are the same object"
if (coin1 == coin2)
    System.out.println("coin1 and coin2 are the same object");
else
    System.out.println("coin1 and coin2 are different objects");
 
String playAgain;
playAgain = "y";

// the condition is false for the same reason as above
if (playAgain == "y")
    System.out.println("playAgain and \"y\" are the same object");
else
    System.out.println("playAgain and \"y\" are different objects");